Answer:
R = 50.016 cm
Explanation:
Coefficient of thermal expansion for steel is given as
[tex]\alpha = 13 \times 10^{-6} per ^0C[/tex]
now as we know that the change in the length due to thermal expansion depends of change in temperature and initial length of the object
so here we will have
[tex]\Delta R = R_o \alpha \Delta T[/tex]
here we know that
[tex]R_o = \frac{50}{2} cm = 25 cm[/tex]
[tex]\Delta T = 50 K[/tex]
now we will have
[tex]\Delta R = (25)(13 \times 10^{-6})(50)[/tex]
[tex]\Delta R = 0.016 cm[/tex]
so final radius of the disc will be R = 50.016 cm
