Answer:
The answer is 52
Step-by-step explanation:
We need figure out the dilated by doing OB’/OB. 5+15= OB’. OB’ = 20. We already know that OB is 5. We used the substitution property. 20/5 = 4. Now, we got 4 as dilation. 13 cm x 4 = 52 cm. Therefore, our answer is 52
Perimeter of ΔA'B'C' is 52 cm.
The perimeter of ΔABC is =13 cm
Length of OB = 5 cm
Length of OB' = 15 + 5 = 20 cm
The Dilation factor can be found out b
ΔOCB and ΔOC'B' are similar as BC|| B'C'
From triangles ΔOCB & ΔOC'B' the dilation factor can be found out
by the formula below
[tex]\frac{BC}{B'C'} = \frac{5}{20}[/tex]
B'C'= 4[tex]\times[/tex]BC
so the dilation factor = 4
hence the new perimeter of the triangle = 13 [tex]\times[/tex] 4 = 52 cm
for more information please refer the link below
https://brainly.com/question/20502441
