Answer:
The wavelength of electron is [tex]6.99\times 10^{-22}\ m[/tex]
Explanation:
The kinetic energy of the electron is, [tex]E=0.5\ MeV=0.5\times 10^6\ eV[/tex]
We need to find the wavelength of this electron. It can be calculated using the concept of DE-broglie wavelength as :
[tex]\lambda=\dfrac{h}{\sqrt{2mE} }[/tex]
h is Plank's constant
m is the mass of electron
[tex]\lambda=\dfrac{6.67\times 10^{-34}\ J-s}{\sqrt{2\times 9.1\times 10^{-31}\ kg\times 0.5\times 10^6\ eV} }[/tex]
[tex]\lambda=6.99\times 10^{-22}\ m[/tex]
So, the wavelength of electron is [tex]6.99\times 10^{-22}\ m[/tex]. Hence, this is the required solution.
