Answer:
[tex]V_{A}= 11.88 m/s[/tex]
Explanation:
given data:
water level at point A = 8 m
diameter of orifice = 0.5 cm
velocity at point A = 0
h1 =0.8 m
h2 = 8 - h1 = 8 - 0.8 = 7.2 m
Applying Bernoulli theorem between point A and B
[tex]P_{o}+\rho _{water}gh_{2}+\frac{1}{2}\rho v_{B}^{2}+\rho _{water}gh_{1}=P_{o} +\frac{1}{2}\rho v_{A}^{2}+\rho _{water}gh_{1}[/tex]
[tex]V_{A}=\sqrt{2gh_{2}}[/tex]
[tex]V_{A}=\sqrt{2*9.81*7.2}[/tex]
[tex]V_{A}= 11.88 m/s[/tex]
