The total solar irradiance (TSI) at Earth orbit is 1400 watts/m2 . Assuming this value can be represented as a single Poynting flux. Find the corresponding flux at the solar visible-light surface. Explain your methods.

(Distance between Sun & Earth is 150 million km)

Respuesta :

Answer:

3.958 × 10²⁶ watt

Explanation:

Given:

Distance between earth and sun, [tex]R_e[/tex] = 150 ×10⁸ m

Total solar irradiance at earth orbit  = 1400 watt/m²

Now,

Area irradiated ([tex]A_e[/tex]) will be = [tex]4\pi R_e^2[/tex]

⇒ [tex]A_e[/tex] =  [tex]4\pi \times (150\times 10^{8})^2[/tex]

⇒ [tex]A_e[/tex] =  [tex]2.827\times 10^{23}m^2[/tex]

Therefore, the flux = Total solar irradiance at earth orbit × [tex]A_e[/tex]

the flux =   [tex]1400watt/m^2\times 2.827\times 10^{23}m^2[/tex]

⇒the flux = 3.958 × 10²⁶ watt