J-s. If your 1400-kg car is parked in an 8.54-m-long garage, what is the uncertainty in its velocity? cm/s the tolerance is +/-2%

Respuesta :

Answer:

[tex]\Delta v = 4.41 \times 10^{-37} cm/s[/tex]

Explanation:

As per Heisenberg's uncertainty principle we know that

[tex]\Delta P \times \Delta x = \frac{h}{4\pi}[/tex]

so here we have

[tex]\Delta P = m\Delta v[/tex]

[tex]\Delta x = 8.54 m[/tex]

now from above equation we have

[tex]m\Delta v \times (8.54) = \frac{h}{4\pi}[/tex]

[tex]1400(\Delta v) \times (8.54) = \frac{6.626 \times 10^{-34}}{4\pi}[/tex]

[tex]\Delta v = 4.41 \times 10^{-39} m/s[/tex]

[tex]\Delta v = 4.41 \times 10^{-37} cm/s[/tex]