Answer : The moles of [tex]CO_2[/tex] produced are, 3.462 moles.
Explanation : given,
Mass of [tex]C_6H_6[/tex] = 45.0 g
Molar mass of [tex]C_6H_6[/tex] = 78 g/mole
First we have to calculate the moles of [tex]C_6H_6[/tex].
[tex]\text{Moles of }C_6H_6=\frac{\text{Mass of }C_6H_6}{\text{Molar mass of }C_6H_6}=\frac{45.0g}{78g/mole}=0.577moles[/tex]
Now we have to calculate the moles of [tex]CO_2[/tex]
The given balanced chemical reaction is,
[tex]2C_6_H6+15O_2\rightarrow 12CO_2+6H_2O[/tex]
From the balanced chemical reaction, we conclude that
As, 2 moles of [tex]C_6H_6[/tex] react to give 12 moles of [tex]CO_2[/tex].
So, 0.577 moles of [tex]C_6H_6[/tex] react to give [tex]\frac{12}{2}\times 0.577=3.462[/tex] moles of [tex]CO_2[/tex].
Therefore, the moles of [tex]CO_2[/tex] produced are, 3.462 moles.
