Answer:
FALSE
Explanation:
As we know that equation for charging of a capacitor is given by
[tex]q = CV(1 - e^{-\frac{t}{\tau}})[/tex]
now at t = 0 we can say there is no charge on the capacitor
now as the time will increase the value of charge will increase on the plates of capacitor
now after t = 1 time constant
we will have
[tex]q = CV(1 - e^{-1})[/tex]
[tex]q = 0.63 CV[/tex]
so after one time constant the capacitor will charged upto 63% of its maximum value.