Explanation:
The weight of the car is equal to, [tex]W_c=m\times g[/tex]...........(1)
Where
m is the mass of car
g is the acceleration due to gravity
The normal or vertical component of the force is, [tex]F_N=mg\ cos\theta[/tex]
or
[tex]F_N=mg\ cos(13)[/tex].............(2)
The horizontal component of the force is, [tex]F_H=mg\ sin\theta[/tex]
Taking ratio of equation (1) and (2) as :
[tex]\dfrac{F_N}{W_c}=\dfrac{mg\ cos\theta}{mg}[/tex]
[tex]\dfrac{F_N}{W_c}=cos(13)[/tex]
[tex]\dfrac{F_N}{W_c}=0.97[/tex]
or
[tex]\dfrac{F_N}{W_c}=\dfrac{97}{100}[/tex]
Hence, this is the required solution.
