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Imagine a population that has 180 A1A1 individuals, 144 A1A2 individuals, and 175 A2A2 individuals. Male A1A1 is the preferred mate of females and gets all the matings. What would the genotype frequencies be for the A1A2 offspring of this population? Answer to 2 decimal places.

Respuesta :

Answer:

[tex]0.288[/tex]

Explanation:

Given

Individuals in a population having genotype A1A1  [tex]= 180[/tex]

Individuals in a population having genotype A1A2  [tex]= 144[/tex]

Individuals in a population having genotype A2A2 [tex]= 175[/tex]

Hence, the total number of individuals in a population [tex]= 180 + 144+ 175\\= 499\\[/tex]

Thus, frequency of Individuals in a population having genotype A1A2 [tex]= \frac{X}{Y}[/tex]

Where X [tex]=[/tex] Individuals in a population having genotype A1A2

Y [tex]=[/tex] total population

Substituting the given values in above equation, we get -

[tex]\frac{144}{499} \\0.288\\[/tex]

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