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Suppose you apply a force of 40 N to a 0.25​-meter-long wrench attached to a bolt in a direction perpendicular to the bolt. Determine the magnitude of the torque when the force is applied at an angle of 135degrees to the wrench.

Respuesta :

Answer:

Torque = 7.07 N.m

Explanation:

It is given that,

Force acting on the wrench, F = 40 N

Length of wrench, l = 0.25 meters

It is attached perpendicular to the bolt such that the force is applied at an angle of 135 degrees to the wrench. The formula for torque is given by :

[tex]\tau=r\times F[/tex]

[tex]\tau=rF\ sin\theta[/tex]

[tex]\tau=0.25\ m\times 40\ N\ sin(135)[/tex]

[tex]\tau=7.07\ N.m[/tex]

So, the magnitude of torque applied to the wrench is 7.07 N-m. Hence, this is the required solution.

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