Answer:
[tex]\overrightarrow{r}=2\widehat{i}-0.75\widehat{j}[/tex]
Step-by-step explanation:
Stagnation point is point of zero velocity thus each component of the velocity must also be zero
[tex]Given\\u=(1-0.5x)[/tex]
[tex]\therefore[/tex] u=0 at x=2m
Similarly
[tex]\\v=(-1.5-2y)\\\\\therefore v=0 \\\\y=\frac{1.5}{-2}\\\\y=-0.75[/tex]
Thus point of stagnation is (2,-0.75)
Thus it's position vector is given by
[tex]\overrightarrow{r}=2\widehat{i}-0.75\widehat{j}[/tex]
