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A capacitor is storing energy of 3 Joules with a voltage of 50 volts across its terminals. A second identical capacitor of the same value is storing energy of 1 Joule. What is the voltage across the terminals of the second capacitor?

Respuesta :

Answer:

28.87 volt

Explanation:

Let the capacitance of the capacitor is C.

Energy, U = 3 J, V = 50 volt

U = 1/2 C V^2

3 = 0.5 x C x 50 x 50

C = 2.4  x 10^-3 F

Now U' = 1 J

U' = 1/2 C x V'^2

1 = 0.5 x 2.4 x 10^-3 x V'^2

V' = 28.87 volt

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