Hydrogen gas and nitrogen gas react to form ammonia gas. What volume of ammonia would be produced by this reaction if 6.9 m3 of hydrogen were consumed? Also, be sure your answer has a unit symbol, and is rounded to the correct number of significant digits.

Respuesta :

Answer:

4600 Liters NH₃(g)

Explanation:

Ver imagen drpelezo

The volume of ammonia that would be produced by this reaction if 6.9 m3 of hydrogen were consumed is 4,600.064cm³

The reaction between the hydrogen gas and nitrogen gas is as given below;

[tex]3H_2+N_2\rightarrow 2NH_3[/tex]

Since the volume of hydrogen is given as 6.9m³

Mole of hydrogen =6900/22.4

Mole of hydrogen = 308.04 moles of H₂

Get the number of moles of NH₃

  • Number of moles of  NH₃ = 2/3 of moles of Hydrogen
  • Number of moles of  NH₃ = 2/3 *  308.04
  • Number of moles of  NH₃ = 205.36 moles of  NH₃

Get the volume of ammonia  NH₃

  • Volume of ammonia produced = 205.36 * 22.4
  • Volume of ammonia produced = 4,600.064cm³

Hence the volume of ammonia that would be produced by this reaction if 6.9 m3 of hydrogen were consumed is 4,600.064cm³

Learn more here: https://brainly.com/question/22411862