Respuesta :
The volume of ammonia that would be produced by this reaction if 6.9 m3 of hydrogen were consumed is 4,600.064cm³
The reaction between the hydrogen gas and nitrogen gas is as given below;
[tex]3H_2+N_2\rightarrow 2NH_3[/tex]
Since the volume of hydrogen is given as 6.9m³
Mole of hydrogen =6900/22.4
Mole of hydrogen = 308.04 moles of H₂
Get the number of moles of NH₃
- Number of moles of NH₃ = 2/3 of moles of Hydrogen
- Number of moles of NH₃ = 2/3 * 308.04
- Number of moles of NH₃ = 205.36 moles of NH₃
Get the volume of ammonia NH₃
- Volume of ammonia produced = 205.36 * 22.4
- Volume of ammonia produced = 4,600.064cm³
Hence the volume of ammonia that would be produced by this reaction if 6.9 m3 of hydrogen were consumed is 4,600.064cm³
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