Explanation:
It is given that,
Speed of proton, [tex]v=10^7\ m/s[/tex]
Acceleration of the proton, [tex]a=2\times 10^{13}\ \ m/s^2[/tex]
The force acting on the proton is balanced by the magnetic force. So,
[tex]ma=qvB\ sin(90)[/tex]
[tex]B=\dfrac{ma}{qv}[/tex]
m is the mass of proton
[tex]B=\dfrac{1.67\times 10^{-27}\ kg\times 2\times 10^{13}\ \ m/s^2}{1.6\times 10^{-19}\times 10^7\ m/s}[/tex]
B = 0.020875
or
B = 0.021 T
So, the magnitude of magnetic field is 0.021 T. As the acceleration in +x direction, velocity in +z direction. So, using right hand rule, the magnitude of B must be in -y direction.
