Answer:
26.8 m/s
Explanation:
[tex]v[/tex] = constant speed of the car
[tex]V[/tex] = speed of sound = 343 m/s
[tex]f[/tex] = actual frequency of the horn
[tex]f_{app}[/tex] = frequency heard as the car approach = 76 Hz
frequency heard as the car approach is given as
[tex]f_{app}=\frac{vf}{V - v}[/tex]
[tex]76 =\frac{vf}{343 - v}[/tex] eq-1
[tex]f_{rec}[/tex] = frequency heard as the car recedes = 65 Hz
frequency heard as the car goes away is given as
[tex]f_{rec}=\frac{vf}{V + v}[/tex]
[tex]65 =\frac{vf}{343 + v}[/tex] eq-2
dividing eq-1 by eq-2
[tex]\frac{76}{65}=\frac{343+v}{343-v}[/tex]
[tex]v[/tex] = 26.8 m/s