Answer:
E= 3.4893 N/C
Explanation:
Given s=6.20 m , t=2.50μs, m=9.11*10^-31 Kg , q= 1.6*10^-19 C
the distance traveled by the electron in time t is
s=ut+0.5at^2
here, u is the initial velocity of the electron, t is time taken and
a is acceleration.
Since the electron is initially at rest u=0
now s=0.5at^2
Therefore a=2s/t^2
also. we know that strength of electric field is
E=ma/q
[tex]E= \frac{2ma}{qt^2}[/tex]
now puting the values we get
[tex]E=\frac{9.11\times 10^-31\times 2\times 6.20}{1.6\times 10^-19\times (4.5\times 10^-6)^2}[/tex]
therefore, E= 3.4865 N/C
