Answer:
2.7 J
Explanation:
The energy of one photon is given by
[tex]E=hf[/tex]
where
h is the Planck constant
f is the frequency
For the photons in this problem,
[tex]f=6.8\cdot 10^9 Hz[/tex]
So the energy of one photon is
[tex]E_1=(6.63\cdot 10^{-34})(6.8\cdot 10^9 )=4.5\cdot 10^{-24} J[/tex]
The number of photons contained in 1.0 mol is
[tex]N_A = 6.022\cdot 10^{23} mol^{-1}[/tex] (Avogadro number)
So the total energy of [tex]N_A[/tex] photons contained in 1.0 mol is
[tex]E=N_A E_1 =(6.022\cdot 10^{23})(4.5\cdot 10^{-24})=2.7 J[/tex]