Respuesta :
Answer:
The pressure of the remaining gas in the tank is 6.4 atm.
Explanation:
Given that,
Temperature T = 13+273=286 K
Pressure = 10.0 atm
We need to calculate the pressure of the remaining gas
Using equation of ideal gas
[tex]PV=nRT[/tex]
For a gas
[tex]P_{1}V_{1}=nRT_{1}[/tex]
Where, P = pressure
V = volume
T = temperature
Put the value in the equation
[tex]10\times V=nR\times286[/tex]....(I)
When the temperature of the gas is increased
Then,
[tex]P_{2}V_{2}=\dfrac{n}{2}RT_{2}[/tex]....(II)
Divided equation (I) by equation (II)
[tex]\dfrac{P_{1}V}{P_{2}V}=\dfrac{nRT_{1}}{\dfrac{n}{2}RT_{2}}[/tex]
[tex]\dfrac{10\times V}{P_{2}V}=\dfrac{nR\times286}{\dfrac{n}{2}R368}[/tex]
[tex]P_{2}=\dfrac{10\times368}{2\times286}[/tex]
[tex]P_{2}= 6.433\ atm[/tex]
[tex]P_{2}=6.4\ atm[/tex]
Hence, The pressure of the remaining gas in the tank is 6.4 atm.
