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A student drops a ball from the top of a 10-meter tall building. The ball leaves the thrower's hand with a zero speed. What is the speed of the ball at the moment just before it hits the ground?

Respuesta :

Answer:

14 m/s

Explanation:

u = 0, h = 10 m, g = 9.8 m/s^2

Use third equation of motion

v^2 = u^2 + 2 g h

Here, v be the velocity of ball as it just strikes with the ground

v^2 = 0 + 2 x 9.8 x 10

v^2 = 196

v = 14 m/s

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