Respuesta :
Answer:
1.586m
Explanation:
let 'u' be the velocity of the roof tile when it reaches the window
now using the equation of motion
[tex]s=ut+\frac{1}{2}at^{2}[/tex]
where s= distance travelled
u=velocity
a=acceleration of the object
t=time taken to travel the distance 's'
given:
s=1.7m (distance covered to pass the window)
t=0.25s (Time taken to pass the window)
a=g=9.8m/s^2 (since the roof tile is moving under the action of gravity)
thus, substituting the values in the above equation we get
[tex]1.7=u\times 0.25+\frac{1}{2}\times 9.8\times0.25^{2}[/tex]
u=5.575m/s
This is the velocity when the tile touches the window top.
Let's take this in second scenario as the tile's final velocity(v).
Now we have another equation of motion as
[tex]v^{2}-u^{2}=2as[/tex]
initial speed (when starts to fall) will be zero.
So the distance travelled (h) i.e the height from which the tile falls from the top of the window is given by,
substituting the values in the above equation, we get
[tex]5.575^{2}-0^{2}=2\times 9.8\times h[/tex]
[tex]h=\frac{5.575^{2}-0^{2}}{2\times 9.8}[/tex]
h=1.586m
Hence, the window roof is 1.586m far away from the roof
