Answer:
42.3 MV
Explanation:
d = diameter of the metal sphere = 2.15 m
r = radius of the metal sphere
diameter of the metal sphere is given as
d = 2r
2.15 = 2 r
r = 1.075 m
Q = charge on sphere = 5.05 mC = 5.05 x 10⁻³ C
Potential near the surface is given as
[tex]V = \frac{kQ}{r}[/tex]
[tex]V = \frac{(9\times 10^{9})(5.05\times 10^{-3})}{1.075}[/tex]
V = 4.23 x 10⁷ volts
V = 42.3 MV
