A proton is placed in a uniform electric field and then released. Then an electron is placed at this same point and released. Which of the following is correct?

The 2 particles experience the same magnitude of force, experience the same magnitude of acceleration, and move in different directions.

The 2 particles experience the same magnitude of force, experience different magnitudes of acceleration, and move in different directions.

The 2 particles experience different magnitudes of force, experience different magnitudes of acceleration, and move in different directions.

The 2 particles experience the same magnitude of force, experience different magnitudes of acceleration, and move in the same direction.

None of the above.

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Vespertilio Vespertilio · Answer 1 · 2019-07-18T03:52:08+02:00

Answer:

option (b)

Explanation:

Let the electric field is given by E.

mass of proton = mp

mass of electron = me

acceleration of proton = ap

acceleration of electron = ae

Charge on both the particle is same but opposite in nature.

The force on proton = q E

The force on electron = - q E

acceleration of proton, ap = q E / mp

acceleration of electron, ae = - q E / me

We observe that the force is same in magnitude but opposite in direction, acceleration is also different and opposite in direction.