Explanation:
It is given that,
Momentum of the photon, [tex]p=5.55\times 10^{-27}\ kg-m/s[/tex]
(a) We need to find the wavelength of this photon. It can be calculated using the concept of De-broglie wavelength.
[tex]\lambda=\dfrac{h}{p}[/tex]
h is the Planck's constant
[tex]\lambda=\dfrac{6.67\times 10^{-34}\ Js}{5.55\times 10^{-27}\ kg-m/s}[/tex]
[tex]\lambda=1.2\times 10^{-7}\ m[/tex]
or
[tex]\lambda=120\ nm[/tex]
(b) The wavelength lies in the group of ultraviolet rays. The wavelength of UV rays lies in between 400 nm to 10 nm.
