Answer:
The radius of the loop is [tex]4.94\times10^{5}\ m[/tex]
Explanation:
Given that,
Current = 0.2kA = 200 A
Number of turns = 35
Magnetic field = 8.9 nT
We need to calculate the radius of one loop
Using formula of magnetic field
[tex]B=\dfrac{N\mu_{0}I}{2r}[/tex]
[tex]r=\dfrac{N\mu_{0}I}{2B}[/tex]
Where, I = current
N = number of turns
B = magnetic field
r = radius
Put the value into the formula
[tex]r=\dfrac{35\times4\pi\times10^{-7}\times200}{2\times8.9\times10^{-9}}[/tex]
[tex]r =494183.11\ m[/tex]
[tex]r=4.94\times10^{5}\ m[/tex]
Hence, The radius of the loop is [tex]4.94\times10^{5}\ m[/tex]
