Answer:
D . 1.47 x 10⁻² Ω-m
Explanation:
L = length of the cylindrical resistor = 2 m
d = diameter = 0.1 m
A = Area of cross-section of the resistor = (0.25) [tex]\pi[/tex] d² = (0.25) (3.14) (0.1)² = 0.785 x 10⁻² m²
V = battery Voltage = 12 volts
[tex]i [/tex] = current flowing through the resistor = 3.2 A
R = resistance of the resistor
Resistance of the resistor is given as
[tex]R = \frac{V}{i}[/tex]
[tex]R = \frac{12}{3.2}[/tex]
R = 3.75 Ω
[tex]\rho[/tex] = resistivity
Resistance is also given as
[tex]R = \frac{ \rho L}{A}[/tex]
[tex]3.75 = \frac{ \rho (2)}{(0.785\times 10^{-2})}[/tex]
[tex]\rho[/tex] = 1.47 x 10⁻² Ω-m
