Answer:
The final velocity of the ball, v = 9.9 m/s
Explanation:
It is given that,
A ball is dropped 5 meters from rest, h = 5 meters
We need to find the final velocity of the ball. It can be calculated using the conservation of energy as :
[tex]KE_i+KE_f=PE_i+PE_f[/tex]
Initial kinetic energy, [tex]KE_i=0\ (rest)[/tex]
Final kinetic energy, [tex]KE_f=\dfrac{1}{2}mv^2[/tex]
Initial potential energy, [tex]PE_i=mgh[/tex]
Final potential energy, [tex]PE_f=0[/tex] (at ground, h = 0)
[tex]\dfrac{1}{2}mv^2=mgh[/tex]
[tex]v=\sqrt{2gh}[/tex]
[tex]v=\sqrt{2\times 9.8\ m/s^2\times 5\ m}[/tex]
v = 9.89 m/s
or
v = 9.9 m/s
So, the final velocity of the ball is 9.9 m/s. Hence, this is the required solution.
