A 9-cm diameter, 11-cm high hollow metal can floats in water vertically with 8 cm of its height under water. What is the weight of the can?

Respuesta :

Answer:

Weight of the can is 5 N

Explanation:

The weight of the can is a downward force. When an object floats in a fluid, it is acted upon by an upward force which balances the weight of the body that acts downwards. This upward force is know as Buoyant force. This buoyant force is also the weight of the fluid displaced by the object.

          Therefore, we know that

Total buoyant force = total weight of the body  

And total weight of the body is nothing but the weight of the fluid displaced by the body.

So, weight of the body = weight of the fluid displaced by the body.

                                      = [tex]\rho g\times[/tex]volume of water displaced by the body.

                                     = [tex]\rho g\times[/tex]volume of the body submerged in the water

Now we know that,

density of water, [tex]\rho[/tex] = 1000 kg/[tex]m^{3}[/tex]

acceleration due to gravity, g = 9.81 m/[tex]s^{2}[/tex]

Volume of the body submerged in water, V = [tex]\frac{\prod }{4}\times d^{2}\times h[/tex]

       = [tex]\frac{\prod }{4}\times 0.09^{2}\times 0.08[/tex]

       = 5.05[tex]\times 10^{-4}[/tex] [tex]m^{3}[/tex]

Therefore, weight of can = [tex]\rho g\times[/tex]volume of the body submerged in the water

                                        = 1000[tex]\times 9.81\times 5.05\times 10^{-4}[/tex]

                                        = 4.95 N

                                        [tex]\simeq[/tex] 5 N

Therefore the weight of the can is 5 N.