Answer:
Number of electrons, [tex]n=5.62\times 10^{21}[/tex]
Explanation:
It is given that,
Resistance, R = 4 ohms
Current, I = 3 A
Time, t = 5 min = 300 s
We need to find the number of electrons pass through the resistor during this time interval. Let the number of electron is n.
i.e. q = n e ...............(1)
And current, [tex]I=\dfrac{q}{t}[/tex]
[tex]I\times t=n\times e[/tex]
[tex]n=\dfrac{It}{e}[/tex]
e is the charge of an electron
[tex]n=\dfrac{3\ A\times 300\ s}{1.6\times 10^{-19}}[/tex]
[tex]n=5.62\times 10^{21}[/tex]
So, the number of electrons pass through the resistor is [tex]5.62\times 10^{21}[/tex]. Hence, this is the required solution.
