Answer:
(a) 21.11 J
(b) 3.3 m/s
Explanation:
(a)
m = mass attached to the spring = 3.95 kg
A = amplitude of the oscillation = 19 cm = 0.19 m
T = Time period of oscillation = 0.365 s
U = Total mechanical energy
Total mechanical energy is given as
[tex]U = (0.5)mA^{2}\left ( \frac{2\pi }{T} \right )^{2}[/tex]
[tex]U = (0.5)(3.95)(0.19)^{2}\left ( \frac{2(3.14) }{0.365} \right )^{2}[/tex]
U = 21.11 J
(b)
v = maximum speed of the mass
maximum speed of the mass is given as
[tex]v = A\left ( \frac{2\pi }{T} \right )[/tex]
[tex]v = (0.19)\left ( \frac{2(3.14) }{0.365} \right )[/tex]
[tex]v [/tex] = 3.3 m/s
