contestada

Glucose, C6H12O6, is used as an energy source by the human body. The overall reaction in the body is described by the equation C6H12O6(aq)+6O2(g)⟶6CO2(g)+6H2O(l) Calculate the number of grams of oxygen required to convert 48.0 g of glucose to CO2 and H2O. mass of O2: g Calculate the number of grams of CO2 produced. mass of CO2: g

Respuesta :

Answer:

70.3824 grams of carbondioxide is produced.

Explanation:

[tex]C_6H_{12}O_6(aq)+6O_2(g)⟶6CO_2(g)+6H_2O(l)[/tex]

Moles of glucose =  [tex]\frac{48.0 g}{180 g/mol}=0.2666 mol[/tex]

According to reaction 1 mole of glucose reacts with 6 mole of oxygen gas.

Then 0.2666 mol of gluocse will reactwith :

[tex]\frac{6}{1}\times 0.2666 mol =1.5996 mol[/tex] of oxygen

Mass of 1.5996 moles of oxygen gas:

[tex]1.5996 mol\times 32 g/mol = 51.1872 g[/tex]

51.1872 grams of oxygen are required to convert 48.0 grams of glucose to [tex]CO_2[/tex] and [tex]H_2O[/tex].

According to reaction, 1 mol, of glucose gives 6 moles of carbon dioxide.

Then 0.2666 moles of glucose will give:

[tex]\frac{6}{1}\times 0.2666 mol =1.5996 mol[/tex] of carbon dioxide

Mass of 1.5996 moles of carbon dioxide gas:

[tex]1.5996 mol\times 44 g/mol = 70.3824 g[/tex]

70.3824 grams of carbondioxide is produced.

dsdrajlin

Glucose reacts with 51.2 g of oxygen to produce 70.4 g of carbon dioxide and water.

Let's consider the overall equation for the combustion of glucose in the human body.

C₆H₁₂O₆(aq) + 6 O₂(g) ⟶ 6 CO₂(g) + 6 H₂O(l)

We can calculate the grams of oxygen required to react with 48.0 g of glucose considering the following relations.

  • The molar mass of glucose is 180.16 g/mol.
  • The molar ratio of glucose to oxygen is 1:6.
  • The molar mass of oxygen is 32.00 g/mol.

[tex]48.0gGlucose \times \frac{1molGlucose}{180.16gGlucose} \times \frac{6molO_2}{1molGlucose} \times \frac{32.00 gO_2}{1 molO_2} = 51.2 gO_2[/tex]

We can calculate the grams of carbon dioxide produced from 48.0 g of glucose considering the following relations.

  • The molar mass of glucose is 180.16 g/mol.
  • The molar ratio of glucose to carbon dioxide is 1:6.
  • The molar mass of carbon dioxide is 44.01 g/mol.

[tex]48.0gGlucose \times \frac{1molGlucose}{180.16gGlucose} \times \frac{6molCO_2}{1molGlucose} \times \frac{44.01 gCO_2}{1 molCO_2} = 70.4 gCO_2[/tex]

Glucose reacts with 51.2 g of oxygen to produce 70.4 g of carbon dioxide and water.

Learn more: https://brainly.com/question/9743981

Otras preguntas