Answer:
5.77 Volt
Explanation:
N = 1000, Diameter = 42 cm = 0.42 m, t = 12 ms = 12 x 10^-3 s
Change in magnetic field, B = 5 x 10^-5 T
The peak value of emf is given by
e = N x dФ / dt
e = N x A x dB/dt
e = (1000 x 3.14 x 0.21 x 0.21 x 5 x 10^-5) / (1.2 x 10^-3)
e = 5.77 Volt
The peak emf generated will be equal to 5.77 Volt
What will be the peak emf?
Given that,
Number of turns n = 1000
Diameter D= 42 cm = 0.42 m,
Time t = 12 milisecomds = [tex]12\times 10^{-3}[/tex] sec
Change in a magnetic field, [tex]B=5\times10^{-5} T[/tex]
The peak value of emf is given by
[tex]e=N\times\dfrac{d\phi }{dt}[/tex]
[tex]e=N\times A\times \dfrac{dB }{dt}[/tex]
[tex]e=\dfrac{(1000\times 3.14\times0.21\times0.21\times5\times10^{-5} )}{1.2\times10^{-3} }[/tex]
[tex]e=5.77 volt[/tex]
Thus the peak emf generated will be equal to 5.77 Volt
To know more about Electromotive force follow
https://brainly.com/question/820393
