Answer:
[tex]y+1=3(x+1)[/tex]
Step-by-step explanation:
Ok so we are looking for line parallel to the line containing points (0,-3) and (2,3).
Parallel lines have the same slope.
So let's find the slope of the line containing the points (0,-3) and (2,3).
You can use the formula [tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex].
However, I just like to line up the points vertically and subtract them vertically, then put 2nd difference over 1st difference. Like this:
(0 , -3)
-(2 , 3)
-----------
-2 -6
So the slope is -6/-2 or just 3.
So the slope of the line we are looking for has slope 3 (or m=3) and your line should contain the point (-1,-1).
The point slope form of a line is:
[tex]y-y_1=m(x-x_1)[/tex] where [tex]m[/tex] is the slope and [tex](x_1,y_1)[/tex] is a point you know on the line.
So we just plug into that equation now. That gives us:
[tex]y-(-1)=3(x-(-1))[/tex]
Simplify a bit:
[tex]y+1=3(x+1)[/tex]
