Answer:
Step-by-step explanation:
Given that A tank holds 17 3/5 gallons after losing 36 2/3 gallons, 4 5/6 gallons,and 27 1/12 gallons in 3
Consecutive days. If at the beginning the tank was 20 3/4 gallons short of capacity.
Tank full capacity = loss for 3 days + holding of tank after losing + shortage of capacity
To add these first let us convert these into improper fractions, then take lcd to add
Full capacity = [tex]\frac{88}{5} +\frac{110}{3} +\frac{29}{6} +\frac{325}{12} \\=\frac{88}{5} +\frac{440+58+325}{12} \\=\frac{1056+4115}{60} =[/tex][tex]=86.183[/tex] gallons
