For triangle ABC, which one is equivalent to sin(A)?
cos(B)
sin(B)
cos(C)
tan(C)

Answer: cos(C)
Step-by-step explanation: Use SohCahToa. Sin(A) is opposite over hypotenuse. The opposite is line BC. Use angle C. To get line BC, you will need the adjacent, and also the hypotenuse. Cos will get you this. Therefore, your answer is Cos(C).
The one which is equivalent to [tex]sin(A)[/tex] will be [tex]Cos(C)[/tex] .
Trigonometric ratios are real functions which relate an angle of a right-angled triangle to ratios of two side lengths.
There are six trigonometric ratios [tex]Sin\theta,Cos\theta,Tan\theta,Cot\theta,Sec\theta,Cosec\theta[/tex] .
We have,
[tex]\triangle ABC[/tex] Right angled at [tex]B[/tex] .
So,
[tex]sin(A)=\frac{Perpendicular}{Height}[/tex]
So, in [tex]\triangle ABC[/tex] ,
[tex]sin(A)=\frac{BC}{AC}[/tex]
Now,
To find its equivalent we will look from angle [tex]C[/tex] ,
So, in options we two trigonometric ratios from angle [tex]C[/tex],
So, take [tex]Cos(C)[/tex] ,
[tex]Cos(C)=\frac{Base}{Hypotenuse}[/tex]
[tex]Cos(C)=\frac{BC}{AC}[/tex]
i.e. Equivalent to [tex]sin(A)[/tex] is [tex]Cos(C)[/tex]
Hence, we can say that the one which is equivalent to [tex]sin(A)[/tex] will be [tex]Cos(C)[/tex] which is in option [tex](c)[/tex] .
To know more about trigonometric ratios click here
https://brainly.com/question/1201366
#SPJ3