In ΔBCA, CA = 15 cm, CF = 7 cm, BH = 3 cm. Find the perimeter of ΔBCA.
25 cm
35 cm
36 cm
46 cm
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Answer:
The perimeter of the triangle is equal to 36 cm
Step-by-step explanation:
we know that
The inscribed circle contained in the triangle BCA is tangent to the three sides
we have that
BF=BH
CF=CG
AH=AG
step 1
Find CG
we know that
CF=CG
so
CF=7 cm
therefore
CG=7 cm
step 2
Find AG
we know that
CA=AG+CG
we have
CA=15 cm
CG=7 cm
substitute
15=AG+7
AG=15-7=8 cm
step 3
Find AH
Remember that
AG=AH
we have
AG=8 cm
therefore
AH=8 cm
step 4
Find BF
Remember that
BF=BH
BH=3 cm
therefore
BF=3 cm
step 5
Find the perimeter of the triangle
P=AH+BH+BF+CF+CG+AG
substitute the values
P=8+3+3+7+7+8=36 cm
The perimeter of ΔBCA (triangle BCA) is 36 cm
The perimeter of a triangle is the sum of the length of the three sides.
The inscribed circle contained in the triangle BCA is tangent to the three sides
Therefore,
BF = BH = 3 cm
CF = CG = 7 cm
AH = AG = 15 - 7 = 8 cm
Therefore,
perimeter = CA + BC + BA
perimeter = 15 + 3 + 7 + 3 + 8
Therefore,
perimeter = 15 + 10 + 11
perimeter = 15 + 21
perimeter = 36 cm
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