Answer:
D
Step-by-step explanation:
Consider the inequality
[tex]\dfrac{x^2+4x-12}{x}>0[/tex]
First, factor the numerator:
[tex]x^2+4x-12=x^2+6x-2x-12=x(x+6)-2(x+6)=(x+6)(x-2)[/tex]
Now, the inequality is
[tex]\dfrac{(x+6)(x-2)}{x}>0[/tex]
The equivalent inequality is
[tex]x(x+6)(x-2)>0[/tex]
On the number line plot doted points -6, 0 and 2 and put signs +, -, +, - from the right to the left. Intervals with + signs are the solution of the inequality:
[tex]x\in(-6,0)\cup(2,\infty)[/tex]
that is represented by D number line.
