Answer:
Part 1) For x=1 year, [tex]y=\$23,750[/tex]
Part 2) For x=2 years, [tex]y=\$22,562.50[/tex]
Part 3) For x=3 years, [tex]y=\$21,434.38[/tex]
Step-by-step explanation:
we know that
The formula to calculate the depreciated value is equal to
[tex]y=P(1-r)^{x}[/tex]
where
y is the depreciated value
P is the original value
r is the rate of depreciation in decimal
x is the number of years
in this problem we have
[tex]P=\$25,000\\r=5\%=0.05[/tex]
substitute
[tex]y=25,000(1-0.05)^{x}[/tex]
[tex]y=25,000(0.95)^{x}[/tex]
Part 1) Find the value of the printer, to the nearest cent, in year 1
so
For x=1 year
substitute in the exponential equation
[tex]y=25,000(0.95)^{1}[/tex]
[tex]y=\$23,750[/tex]
Part 2) Find the value of the printer, to the nearest cent, in year 2
so
For x=2 years
substitute in the exponential equation
[tex]y=25,000(0.95)^{2}[/tex]
[tex]y=\$22,562.50[/tex]
Part 3) Find the value of the printer, to the nearest cent, in year 3
so
For x=3 years
substitute in the exponential equation
[tex]y=25,000(0.95)^{3}[/tex]
[tex]y=\$21,434.38[/tex]