Respuesta :

Step-by-step explanation:

for a³b²c-1d

given

a=2

b=4

c=10

d=15

a³b²c-¹d

=(2³4²10^-1*15

=2³4²15/10

=8*16*15/10

=8*8*3

=64*3

=192

now

a³b²c¹d

=(2³4²10 15)

=(8*16*10*15)

=120*16*10

=1200*16

=19200

Answer:

3/4 if meant [tex]a=2,b=4,c=10,d=15[/tex]

is [tex]a^3b^{-2}c^{-1}d[/tex]

Step-by-step explanation:

So the expression we want to evaluate for [tex]a=2,b=4,c=10,d=15[/tex]

is [tex]a^3b^{-2}c^{-1}d[/tex]

Please make sure I typed the expression and the values for the letters right.

[tex]a^3b^{-2}c^{-1}d[/tex]

Plug in the given values:

[tex](2)^3(4)^{-2}(10)^{-1}(15)[/tex]

In the following step I said 2^3 equals 8 because 2^3 means 2*2*2.  I also got rid of the negative exponents by taking reciprocal.

[tex]8 \cdot \frac{1}{4^2} \cdot \frac{1}{10^1} (15)[/tex]

In the following step I said 4^2=16 because 4^2 means 4*4.  I also wrote 10^1 as 10.

[tex]8 \cdot \frac{1}{16} \cdot \frac{1}{10} (15)[/tex]

In the following step, I'm going to rewrite everything as a fraction if it isn't already a fraction.  8=8/1 and 15=15/1.

[tex]\frac{8}{1} \cdot \frac{1}{16} \cdot \frac{1}{10} \cdot \frac{15}{1}[/tex]

To multiply fractions, you just multiply straight across on top and straight across on bottom.

[tex]\frac{8(1)(1)(15)}{1(16)(10)(1)}[/tex]

Actually performing the multiplication:

[tex]\frac{120}{160}[/tex]

Time to reduce:

[tex]\frac{12}{16}[/tex] I divided top and bottom by 10 to get this.

One more time for reducing:

[tex]\frac{3}{4}[/tex] I divided top and bottom by 4 to get this.