Respuesta :
Step-by-step explanation:
for a³b²c-1d
given
a=2
b=4
c=10
d=15
a³b²c-¹d
=(2³4²10^-1*15
=2³4²15/10
=8*16*15/10
=8*8*3
=64*3
=192
now
a³b²c¹d
=(2³4²10 15)
=(8*16*10*15)
=120*16*10
=1200*16
=19200
Answer:
3/4 if meant [tex]a=2,b=4,c=10,d=15[/tex]
is [tex]a^3b^{-2}c^{-1}d[/tex]
Step-by-step explanation:
So the expression we want to evaluate for [tex]a=2,b=4,c=10,d=15[/tex]
is [tex]a^3b^{-2}c^{-1}d[/tex]
Please make sure I typed the expression and the values for the letters right.
[tex]a^3b^{-2}c^{-1}d[/tex]
Plug in the given values:
[tex](2)^3(4)^{-2}(10)^{-1}(15)[/tex]
In the following step I said 2^3 equals 8 because 2^3 means 2*2*2. I also got rid of the negative exponents by taking reciprocal.
[tex]8 \cdot \frac{1}{4^2} \cdot \frac{1}{10^1} (15)[/tex]
In the following step I said 4^2=16 because 4^2 means 4*4. I also wrote 10^1 as 10.
[tex]8 \cdot \frac{1}{16} \cdot \frac{1}{10} (15)[/tex]
In the following step, I'm going to rewrite everything as a fraction if it isn't already a fraction. 8=8/1 and 15=15/1.
[tex]\frac{8}{1} \cdot \frac{1}{16} \cdot \frac{1}{10} \cdot \frac{15}{1}[/tex]
To multiply fractions, you just multiply straight across on top and straight across on bottom.
[tex]\frac{8(1)(1)(15)}{1(16)(10)(1)}[/tex]
Actually performing the multiplication:
[tex]\frac{120}{160}[/tex]
Time to reduce:
[tex]\frac{12}{16}[/tex] I divided top and bottom by 10 to get this.
One more time for reducing:
[tex]\frac{3}{4}[/tex] I divided top and bottom by 4 to get this.