Answer:
So you will want to graph the following 3 points:
(0,2)
(3,3)
(-3,1)
Then connect the points.
Step-by-step explanation:
So we have the equation x-3y=-6.
I'm going to solve for y once so I don't have to do it 3 times when choosing a value for x.
x-3y=-6
Subtract x on both sides:
-3y=-x-6
Divide both sides by -3:
[tex]y=\frac{-x}{-3}+\frac{-6}{-3}[/tex]
Simplify where you can:
[tex]y=\frac{1}{3}x+2[/tex]
So since this in the slope-intercept form, y=mx+b where slope is m and b is y-intercept we have that (0,2) is on our line. If you plug in 0, you will get 2 like this y=1/3 (0)+2=0+2=2.
Now I'm going to choose easy values to plug in, ones that are divisible by 3 since x is being multiplied by 1/3.
So if x=3, then [tex]y=\frac{1}{3}(3)+2=1+2=3[/tex], so (3,3) is on the line.
So if x=-3, then [tex]y=\frac{1}{3}(-3)+2=-1+2=1[/tex]. so (-3,1) is on the line.
So you will want to graph the following 3 points:
(0,2)
(3,3)
(-3,1)
