Answer:
i) 4π
ii) An isosceles triangle
iii) 8 cm^2[/tex]
iv) [tex](4\pi - 8)cm^2[/tex]
Step-by-step explanation:
The radius of the circle is 4 cm and the measure of the central angle is 90°.
We know that the area of sector of a circle = [tex]\frac{central angle}{360} *\pi *r^2[/tex]
Given: r = 4 and central angle = 90
Now plug in these values in the above formula, we get
Area of the sector = [tex]\frac{90}{360} *\pi *4^2\\= \frac{1}{4} *\pi *16\\= 4\pi[/tex]
i) 4π
ii) In the triangle, the two sides are equal in measure, because the two sides represents the radius of the circle. The radius are the same in measure in a circle.
Therefore, the triangle is the second is an isosceles triangle.
iii) Area of a right triangle = [tex]\frac{1}{2} *base*height[/tex]
Here base = 4 and height = 4, plug in these values in the triangle formula, we get
The area of the triangle = [tex]\frac{1}{2} *4*4\\= 2*4\\= 8 cm^2[/tex]
iv) The area of the segment of the circle is (4π - area of the triangle).
= [tex](4\pi - 8)cm^2[/tex]