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Easter Island is a small island in the southern Pacific Ocean. It lies approximately 3,500 kilometers east of Chile and is considered one of the most remote islands. It is also a volcanic island. In 2025, Easter Island had a population of 16,000. However, many of the island’s residents were killed during a series of volcanic eruptions that occurred in the year 2065. Of the original population, only 200 people survived. It is now 100 years later, and the population of Easter Island has reached 800. Of the current population, 328 people are homozygous recessive for Marfan syndrome, which is autosomal (mm genotype). Marfan syndrome is a genetic disorder that affects the connective tissue. Symptoms of Marfan syndrome include increased height, thinness, flexible joints, heart complications, and long arms, legs, fingers, and toes.
q^2 -
q -
p -
p^2 -
2pq -
Use this information to help you answer the following questions:
The original population’s actual genotype frequencies were: MM – 0.42, Mm – 0.13, mm – 0.45.
1.) Is the current population in Hardy - Weinberg equilibrium? Yes or No
2.) Is the current population evolving? Yes or No
3.) If the current population is evolving, what type of effect is responsible for genetic drift?

Respuesta :

Answer:

Explanation:Define as it relates to adaptation

A. Yes, the current population in Hardy - Weinberg equilibrium follows.

p = 0.36 (dominant allele)

q = 0.64 (recessive allele)

p² = 0.13

2pq = 0.46

q² = 0.41

What is hardy Weinberg equation?

The Hardy-Weinberg equation is a mathematical equation used to calculate the genetic variation of a population at equilibrium.

Here, we need to use the Hardy-Weinberg equations:

p + q = 1

p² + 2pq + q² = 1

p: the frequency of the dominant allele

q: the frequency of the recessive allele

p²: the frequency of homozygous dominant

2pq: the frequency of heterozygous

: the frequency of homozygous recessive

Here, we know that 328/800 people are homozygous recessive, which means that q² = 328/800 = 0.41.

Then, q = √0.41 = 0.64, and p = 1 - q = 1 - 0.64 = 0.36.

Now, we have p² = (0.36)² = 0.1296 ≈ 0.13 and 2pq = 2 * 0.36 * 0.64 = 0.4608 ≈ 0.46.

Final answer:

p = 0.36

q = 0.64

p² = 0.13

2pq = 0.46

q² = 0.41

B. To know if a population is in Hardy-Weinberg Equilibrium scientists have to observe at least two generations. If the allele frequencies are the same for both generations then the population is in Hardy-Weinberg Equilibrium. Yes, the current population in Hardy - Weinberg equilibrium.

For more information regarding Hardy Weinberg equation, visit:

https://brainly.com/question/5028378

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