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PLEASE HELP ME!!!
Find p(–5) and p(3) for the function p(x) = 2x5 – 9x4 – 2x2 + 12x – 2. Question 8 options: –11,915; –251 –4,487; –551 –11,985; –225 –11,987; –227

Respuesta :

frika

Answer:

p(-5)=-11,987

p(3)=-227

Step-by-step explanation:

To find the value of the function p(-5) just substitute x=-5 into the function expression instead of x:

[tex]p(-5)=2\cdot (-5)^5-9\cdot (-5)^4-2\cdot (-5)^2+12\cdot (-5)-2=\\ \\=-6,250-5,625-50-60-2=-11,987[/tex]

To find the value of the function p(3) just substitute x=3 into the function expression instead of x:

[tex]p(3)=2\cdot 3^5-9\cdot 3^4-2\cdot 3^2+12\cdot 3-2=\\ \\=486-729-18+36-2=-227[/tex]

Answer with Step-by-step explanation:

We are given a function:

[tex]p(x) = 2x^5-9x^4-2x^2+12x-2[/tex]

We have to find the value of p(-5) and p(3)

[tex]p(-5) = 2\times (-5)^5-9\times (-5)^4-2\times (-5)^2+12\times (-5)-2\\\\=-6250-5625-50-60-2\\\\=-11987[/tex]

[tex]p(3) = 2\times 3^5-9\times 3^4-2\times 3^2+12\times 3-2\\\\=486-729-18+36-2\\\\=-227[/tex]

Hence, p(-5)= -11987

and p(3)= -227