Answer:
0.018 J
Explanation:
The work done to bring the charge from infinity to point P is equal to the change in electric potential energy of the charge - so it is given by
[tex]W = q \Delta V[/tex]
where
[tex]q=3.0 \mu C = 3.0 \cdot 10^{-6} C[/tex] is the magnitude of the charge
[tex]\Delta V = 6.0 kV = 6000 V[/tex] is the potential difference between point P and infinity
Substituting into the equation, we find
[tex]W=(3.0\cdot 10^{-6}C)(6000 V)=0.018 J[/tex]
