The answer is:
The correct option is the option D
[tex]g=1.63\frac{m}{s^{2}}[/tex]
To calculate the acceleration, we need to use the following formula that involves the given information (initial speed, final speed, and time).
We need to use the following free fall equation:
[tex]V_{f}=V_{o}-g*t[/tex]
Where:
[tex]V_{f}[/tex] is the final speed.
[tex]V_{o}[/tex] is the initial speed.
g is the acceleration due to gravity.
t is the time.
We are given the following information:
[tex]V_{f}=8.15\frac{m}{s}[/tex]
[tex]V_{o}=0\frac{m}{s}[/tex]
[tex]t=5seconds[/tex]
Then, using the formula to isolate the acceleration, we have:
[tex]V_{f}=V_{o}-g*t[/tex]
[tex]V_{f}=V_{o}-g*t\\\\g*t=V_{o}-V_{f}\\\\g=\frac{V_{o}-V_{f}}{t}[/tex]
Now, substituting we have:
[tex]g=\frac{V_{o}-V_{f}}{t}[/tex]
[tex]g=\frac{0-8.15\frac{m}{s}}{5seconds}=-1.63\frac{m}{s^{2}}[/tex]
Therefore, since we are looking for a magnitude, we have that the obtained value will be positive, so:
[tex]g=1.63\frac{m}{s^{2}}[/tex]
Hence, the correct option is the option D
[tex]g=1.63\frac{m}{s^{2}}[/tex]
Have a nice day!
