A 20 liter cylinder of helium at a pressure of 150 atm and a temperature of 27°C is used to fill a balloon at 1.00 atm and 37°C. What is the volume of the balloon?
A.
0.14 liters
B.
3000 liters
C.
2900 liters
D.
2400 liters
E.
3100 liters

Respuesta :

Answer:The number of moles will remain the same in the two cases

so we can equate using ideal gas equation which is PV =nRT

V2 = 3100 L

Explanation:

Answer: E.   3100 liters

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]

where,

[tex]P_1[/tex] = initial pressure of gas = 150 atm

[tex]P_2[/tex] = final pressure of gas = 1 atm

[tex]V_1[/tex] = initial volume of gas = 20 L

[tex]V_2[/tex] = final volume of gas = ?

[tex]T_1[/tex] = initial temperature of gas = [tex]27^oC=273+27=300K[/tex]

[tex]T_2[/tex] = final temperature of gas = [tex]37^oC=273+37=310K[/tex]

Now put all the given values in the above equation, we get the final pressure of gas.

[tex]\frac{150atm\times 20L}{300K}=\frac{1atm\times V_2}{310K}[/tex]

[tex]V_2=3100L[/tex]

Therefore, the volume of the baloon is 3100 L.