Answer:
B. 44.2 cm3
Step-by-step explanation:
we know that
If the cross-sectional area parallel to the bases of the two figures above is the same at every level
then
the area of the base of the triangular pyramid is the same that the area of the base of the cone
step 1
Find the area of the base of the pyramid
[tex]A=(1/2)[6*4.8]=14.4\ cm^{2}[/tex]
step 2
Find the volume of the cone
The volume of the cone is equal to
[tex]V=\frac{1}{3}Bh[/tex]
we have
[tex]B=14.4\ cm^{2}[/tex]
[tex]h=9.2\ cm[/tex]
substitute
[tex]V=\frac{1}{3}(14.4)(9.2)[/tex]
[tex]V=44.2\ cm^{3}[/tex]
