In the figure, AB∥CD. Find x and y.
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Answer:
y=131°
x=53°
Step-by-step explanation:
∠ ABD and ∠ BDC are supplementary.
The sum of the supplementary angles =180 °
thus y-4+x=180...........i
x and 37° are complementary, that is, they add up to 90°
Thus, x=90-37=53°
Using this value in equation 1 we obtain:
y-4°+53° =180°
y= 180°-53°+4°
y=131°
Answer:
x = 53°
y = 131°
Step-by-step explanation:
From the figure we can see a right angled triangle.
AB∥CD
To find the value of x and y
Consider the large triangle, by using angle sum property we can write,
90 + 37 + x = 180
127 + x = 180
x = 180 - 127
x = 53°
Since AB∥CD and BD is a traversal on these parallel lines.
Therefore <ABD and < CDB are supplementary
we have x = 53°,
x + (y - 4) = 180
53 + y - 4 = 180
y = 180 - 49 = 131°
y = 131°