Answer:
see explanation
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = (- 3, 2) and (x₂, y₂ ) = (0, 4) ← 2 points on the line
m = [tex]\frac{4-2}{0+3}[/tex] = [tex]\frac{2}{3}[/tex]
note the line crosses the y- axis at (0, 4) ⇒ c = 4, hence
y = [tex]\frac{2}{3}[/tex] x + 4 ← in slope- intercept form
OR
the equation of a line in point- slope form is
y - b = m(x - a)
where m is the slope and (a, b) a point on the line
here m = [tex]\frac{2}{3}[/tex] and (a, b) = (3, 6), hence
y - 6 = [tex]\frac{2}{3}[/tex](x - 3) ← in point- slope form
