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A volleyball player’s hand applies a 39 N force while in contact with a volleyball for 2 seconds. What is the impulse on the ball? 20 N • s 37 N • s 41 N • s 78 N • s

Respuesta :

skyluke89

Answer:

78 N s

Explanation:

The impulse exerted on the ball is given by:

[tex]I = F \Delta t[/tex]

where

F is the magnitude of the force

[tex]\Delta t[/tex] is the duration of the collision

In this problem,

F = 39 N

[tex]\Delta t = 2 s[/tex]

Substituting,

[tex]I=(39 N)(2 s)= 78 Ns[/tex]